What are at least four factors of 3402?

Answer 1

4 factors of 3402 are: 2, 3, 6, 7

3402= 1 * 2 * 3 * 3 * 3 * 3 * 3 * 7

hence the prime factors of 3402 are: 2, 3, 7

any number which can represented as a multiple of these digits is a factor of the give number.

Note: use each digit once only, while multiplying to obtain a factor; however the digit 3 may be used 5 times as it appears 5 times while factoring 3402.