Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
The four consecutive integers with the sum of -66 are -18, -17, -16 and -15.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of the first four non-negative, consecutive, even integers is 20.
The smallest is -1
-66 and -68
There are none.
If n is the smallest of the four integers, their sum is 4n+6.
14, 15, 16 and 17.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
There is a set of four consecutive even integers whose sum is four. The set is: -2, 0, 2 and 4.
They are odd consecutive integers: 21, 23, 25 and 27.