Na+ and Cl- are spectator ions.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
FeCl3
Calcium Chloride
No. Convert to the same units then a comparison can be made. 1l = 100 cl → 4 l = 4 × 100 cl = 400 cl < 517 cl → 4 l is less than 517 cl.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Na+ and Cl-
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
Na+, K+,Li+, NH4 + and NO3 - are always spectator ions because they are always soluble
The spectator ions in the reaction between BaCl2 and Na2SO4 are Na+ and Cl-. These ions do not participate in the reaction and remain in the solution unchanged.
When Rb2O and CaCl2 are added together, the resulting spectator ions are Cl^- and Rb^+ ions. This is because the Rb^+ ions from Rb2O do not participate in the reaction, and the Cl^- ions from CaCl2 similarly remain unchanged. The reaction forms CaO and RbCl as the products.
The spectator ions in this reaction are K+ and SO4^2-. These ions do not participate in the chemical reaction and remain unchanged on both sides of the equation.
The net ionic equation is Cd2+(aq) + S2-(aq) -> CdS(s). This equation represents the actual chemical change happening in the reaction where cadmium ions and sulfide ions combine to form solid cadmium sulfide. The spectator ions, Na+ and Cl-, are present on both sides of the equation but do not participate in the reaction.
When KCl is dissolved in water, it dissociates into K+ ions and Cl- ions. These ions are responsible for conducting electricity in the solution.
Na+( ion) + Cl- ( ion) + H2O It gets dissociated into ions.
The equation for lithium chloride (LiCl) dissolving in water is LiCl(s) + H2O(l) -> Li+(aq) + Cl-(aq). This reaction shows the dissociation of LiCl into lithium ions (Li+) and chloride ions (Cl-) in aqueous solution.
In NaCl solutions, the most likely particles present are Na+ ions and Cl- ions. In sucrose solutions, the most likely particles present are sucrose molecules (C12H22O11).