Na+ and Cl- are spectator ions.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
FeCl3
Calcium Chloride
No. Convert to the same units then a comparison can be made. 1l = 100 cl → 4 l = 4 × 100 cl = 400 cl < 517 cl → 4 l is less than 517 cl.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Na+ and Cl-
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
The spectator ions in the reaction between BaCl2 and Na2SO4 are Na+ and Cl-. These ions do not participate in the reaction and remain in the solution unchanged.
Na+, K+,Li+, NH4 + and NO3 - are always spectator ions because they are always soluble
When Rb2O and CaCl2 are added together, the resulting spectator ions are Cl^- and Rb^+ ions. This is because the Rb^+ ions from Rb2O do not participate in the reaction, and the Cl^- ions from CaCl2 similarly remain unchanged. The reaction forms CaO and RbCl as the products.
The spectator ions in this reaction are K+ and SO4^2-. These ions do not participate in the chemical reaction and remain unchanged on both sides of the equation.
The net ionic equation is Cd2+(aq) + S2-(aq) -> CdS(s). This equation represents the actual chemical change happening in the reaction where cadmium ions and sulfide ions combine to form solid cadmium sulfide. The spectator ions, Na+ and Cl-, are present on both sides of the equation but do not participate in the reaction.
When KCl is dissolved in water, it dissociates into K+ ions and Cl- ions. These ions are responsible for conducting electricity in the solution.
Na+( ion) + Cl- ( ion) + H2O It gets dissociated into ions.
In NaCl solutions, the most likely particles present are Na+ ions and Cl- ions. In sucrose solutions, the most likely particles present are sucrose molecules (C12H22O11).
The equation for lithium chloride (LiCl) dissolving in water is LiCl(s) + H2O(l) -> Li+(aq) + Cl-(aq). This reaction shows the dissociation of LiCl into lithium ions (Li+) and chloride ions (Cl-) in aqueous solution.