The multiples of 5 that are also multiples of 6 are multiples of their LCM. The LCM of 5 and 6 is 30, so the question becomes which multiples of 30 are less than 100? The solution is the numbers: 30, 60, 90
20
-15
The main generalization you can make about all multiples of 5 would be that they will either end in the digit 0 or 5. So 5, 487975, 100, and so on all are multiples of 5. I don't believe there are any other generalizations that can be made about it.
1 ÷ 5 = 0 r 1 → first multiple of 5 in the range 1-100 is 1 x 5 = 5 100 ÷ 5 = 20 → last multiples of 5 in the range 1-100 is 20 x 5 = 100 → want the first 20 multiples of 5, namely: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100.
Oh, dude, let me break it down for you. So, the factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. Out of these, the multiples of 5 are 5, 10, 20, 25, 50, and 100. That's like 6 factors of 100 that are multiples of 5. Easy peasy, lemon squeezy!
The multiples of 5 that are also multiples of 6 are multiples of their LCM. The LCM of 5 and 6 is 30, so the question becomes which multiples of 30 are less than 100? The solution is the numbers: 30, 60, 90
20
There are an infinite number of multiples of 100. 100, 200, 300,400, ....
20,40,60,80,and 100
5,10,15,20,25,30,35,40,45,50,55,60
5, 10, 15 and just keep adding 5 until you get to 100.
100, 200, 300, 400, 500.
If 100-300 is inclusive, the answer is 41.
100, 200, 300, 400, 500
The highest power of 25 that divides the product of the first 100 multiples of 5 is 50. This is because for each multiple of 25, we have an extra factor of 25. Since there are 4 multiples of 25 in the first 100 multiples of 5, we have a total of 50 factors of 25.
100 is a multiple of 5. For it to be common, it needs to be compared to another set of multiples.