91
100, 110 and 120 are 3 digit multiplies of 10.
It must be the 9, since 9,000,000 is greater than 10 times 300,000.The answer should not be the 7 since 70 is equalto 10 times 7, not greater than.
10
8100
50, 60, 70, 80, 90
There is no single digit number greater than 9. After 9 is 10, which is a double-digit number.
91
No, since 60 is (greater than 0 and) less than 122515 and all multiples of 122515 are greater than, or equal to, 122515. Neither is 60 a factor of 122515 (22515 a multiple of 60) since 60 is a multiple of 10 and all multiples of 10 end in a zero (ie the units digit is zero) but 122515 does not end in a zero and so cannot be a multiple of 10, nor 60.
100, 110 and 120 are 3 digit multiplies of 10.
It must be the 9, since 9,000,000 is greater than 10 times 300,000.The answer should not be the 7 since 70 is equalto 10 times 7, not greater than.
16
Meaningless question.
list the first 10 common mutiles of 2,and 4 greater than 0
Ignoring digits after the decimal point, if the number of digits in the numerator is at least two more than the number of digits in the denominator then the quotient is greater than 10.If the number of digits is only one more, then the first digit of the numerator must be greater than the first digit if the denominator. If they are the same, then the second digit of the N must be greater than the second digit of the D. If they are the same, compare the third digits and so on.Other wise, the quotient is not greater than 10.For example, you can multiply the divisor by 10 (just add a zero, if it's a whole number), and check whether the divident is greater than that, or not.
Prime numbers greater than 10 will only end in 1, 3, 7 or 9.
10