Well, honey, the 2 digit multiples of 10 greater than 25 are 30, 40, 50, 60, 70, 80, and 90. So, you've got quite a few options there. Just pick one and run with it!
The multiples of 10 are numbers that can be evenly divided by 10. In the case of 3-digit multiples of 10, the smallest 3-digit multiple of 10 is 100 (10 x 10), and the largest 3-digit multiple of 10 is 990 (10 x 99). Therefore, the 3-digit multiples of 10 range from 100 to 990, inclusive.
91
It must be the 9, since 9,000,000 is greater than 10 times 300,000.The answer should not be the 7 since 70 is equalto 10 times 7, not greater than.
10
8100
50, 60, 70, 80, 90
There is no single digit number greater than 9. After 9 is 10, which is a double-digit number.
The multiples of 10 are numbers that can be evenly divided by 10. In the case of 3-digit multiples of 10, the smallest 3-digit multiple of 10 is 100 (10 x 10), and the largest 3-digit multiple of 10 is 990 (10 x 99). Therefore, the 3-digit multiples of 10 range from 100 to 990, inclusive.
91
No, since 60 is (greater than 0 and) less than 122515 and all multiples of 122515 are greater than, or equal to, 122515. Neither is 60 a factor of 122515 (22515 a multiple of 60) since 60 is a multiple of 10 and all multiples of 10 end in a zero (ie the units digit is zero) but 122515 does not end in a zero and so cannot be a multiple of 10, nor 60.
To determine how many times greater the digit in the ten thousands place is than the digit in the hundreds place, we need to understand the positional value of each digit. The positional value of a digit increases by a factor of 10 as you move from right to left in a number. Therefore, the digit in the ten thousands place is 10 times greater than the digit in the hundreds place.
It must be the 9, since 9,000,000 is greater than 10 times 300,000.The answer should not be the 7 since 70 is equalto 10 times 7, not greater than.
16
list the first 10 common mutiles of 2,and 4 greater than 0
Meaningless question.
Ignoring digits after the decimal point, if the number of digits in the numerator is at least two more than the number of digits in the denominator then the quotient is greater than 10.If the number of digits is only one more, then the first digit of the numerator must be greater than the first digit if the denominator. If they are the same, then the second digit of the N must be greater than the second digit of the D. If they are the same, compare the third digits and so on.Other wise, the quotient is not greater than 10.For example, you can multiply the divisor by 10 (just add a zero, if it's a whole number), and check whether the divident is greater than that, or not.
Prime numbers greater than 10 will only end in 1, 3, 7 or 9.