8100
60 numbers
-3
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
To determine the number of 3-digit numbers that are multiples of 5, we need to find the first and last 3-digit multiples of 5. The first 3-digit multiple of 5 is 100, and the last 3-digit multiple of 5 is 995. To find the total number of such multiples, we can use the formula (Last - First) / 5 + 1 = (995 - 100) / 5 + 1 = 180. Therefore, there are 180 3-digit numbers that are multiples of 5.
A zero at the end.
Multiples of 30 from 120 to 990
lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.
There are 49 3-digit numbers - from 108 to 990 inclusive.
All integers have an infinite amount of multiples.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
8100
81
10 of them.
There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
It is the integer that you get by dividing the three digit number by 10. Alternatively, the number of the multiples of ten is that you get when you truncate the rightmost number. for example assume a three digit number 517 Divide 517 by ten, you get 51.7 The integer number is 51 Alternatively, if you trnucate the rightmost number (7) you get 51 also then the answer the three digit number 517 has 51 multiples of 10.