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Just find the midpoint of opposite corners
Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)].
1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated:
XC = XA + (XB-XA)/2
YC = YA - (YA-XB)/2
2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated:
XC = XA + (W)/2
YC = YA - (W)/2
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Does a rectangle have point symmetry?
Yes. In 3 dimensions, a rectangle has 3 C2 axes perpendicular to each other and an inversion center at the center of the rectangle. There are also reflection planes along each of the C2 axes; this makes the point group of the rectangle D2h.
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You plot both coordinates together.
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90 Degrees exact
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