Just find the midpoint of opposite corners
Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)].
1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated:
XC = XA + (XB-XA)/2
YC = YA - (YA-XB)/2
2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated:
XC = XA + (W)/2
YC = YA - (W)/2
Yes. In 3 dimensions, a rectangle has 3 C2 axes perpendicular to each other and an inversion center at the center of the rectangle. There are also reflection planes along each of the C2 axes; this makes the point group of the rectangle D2h.
The vertex is at (5, -5).
A rectangle has NO faces. A rectangle has FOUR(4) Sides.
... right angles, by definition of a rectangle.... right angles, by definition of a rectangle.... right angles, by definition of a rectangle.... right angles, by definition of a rectangle.
The center of a square is half-way up one side and half-way along the adjacent side, and the sides are the same in a square, so you might say, "1/2A, 1/2A" for the center of a square with one corner at the origin of the axes and having size of A.
It depends on what the coordinates of the first three vertices are!
No- the vertices of a rectangle are the four coordinates (corners) not the midpoints.
90 Degrees exact
The formula for the center of gravity of a rectangle is: X = (W/2) and Y = (H/2), where X is the distance from the side of the rectangle to the center and Y is the distance from the top of the rectangle to the center, W is the width of the rectangle, and H is the height of the rectangle.
(40, 45) The center point is half way along the width and half way up the height; thus the center coordinates are: (25 + 30/2, 25 + 40/2) = (25 + 15, 25 + 20) = (40, 45)
multiply width times length
-a, b
The first step to finding a triangle's center of gravity is to calculate the average of the x-coordinates and y-coordinates of the triangle's vertices. This will give you the coordinates of the centroid, which is the point where the center of gravity lies.
centre it and that is the answer
-24.046464, 135.864256
Without further information, the coordinates could be any ordered triplet.
To determine the coordinates of the fourth vertex of a rectangle, you need to know the coordinates of the other three vertices. If you have the coordinates of three vertices, you can find the fourth by using the properties of a rectangle, where opposite sides are equal and the diagonals bisect each other. For example, if the vertices are A(x1, y1), B(x2, y2), and C(x3, y3), you can find the fourth vertex D(x4, y4) through the midpoint formula or by ensuring that the lengths of the sides and the diagonals are consistent. Please provide the coordinates of the existing vertices for a specific answer.