The center of a square is half-way up one side and half-way along the adjacent side, and the sides are the same in a square, so you might say, "1/2A, 1/2A" for the center of a square with one corner at the origin of the axes and having size of A.
Clockwise from top right: (4,4); (4,-4); (-4,-4); (-4,4)
2,1 6,1 2,5 and
The idea is to calculate the average of the x-coordinates (this will be the x-coordinate of the answer), and the average of the y-coordinates (this will be the y-coordinate of the answer).
Find ab
square root of 90
The first step to finding a triangle's center of gravity is to calculate the average of the x-coordinates and y-coordinates of the triangle's vertices. This will give you the coordinates of the centroid, which is the point where the center of gravity lies.
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
To get the coordinates of a square, you need to know the position of one vertex and the length of the sides. Assuming the square is aligned with the axes, if you have the coordinates of the bottom-left vertex (x, y) and the side length (s), the coordinates of the square's vertices would be (x, y), (x+s, y), (x, y+s), and (x+s, y+s). If the square is rotated or positioned differently, you may need additional information, such as the angle of rotation or the center point.
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
Clockwise from top right: (4,4); (4,-4); (-4,-4); (-4,4)
You need two coordinates, not one, to specify a point. To calculate the slope, simply calculate (difference in y-coordinates) / (difference in x-coordinates).
By using the distance formula. We calculate the difference of the like coordinates (e.g longitude1-longitude2 or latitude1-latitude2 etc) then add the "squares" of the differences. And finally taking the square root of the answer.
To find the area of a square, we need the length of one side. The given coordinates appear to be the x-coordinates of the vertices, but without the corresponding y-coordinates, we cannot determine the vertices' positions or calculate the side length. Assuming the vertices were intended to be (36, 31), (-21, 31), (-21, -26), and (36, -26), the side length would be the difference in the x-coordinates, which is 36 - (-21) = 57. Thus, the area would be (57^2 = 3249) square units.
In the algebraic equation for a circle. (x - g)^2 + (y - h)^2 = r^2 'g' & 'h' are the centre of rotation.
To calculate the square footage of a regular pentagon (where all sides and angles are equal), you can use the formula: ( \text{Area} = \frac{1}{4} \sqrt{5(5 + 2\sqrt{5})} s^2 ), where ( s ) is the length of a side. For an irregular pentagon, you can divide it into simpler shapes (like triangles) to calculate the area of each and then sum them up. Alternatively, you can use the coordinates of the vertices with the shoelace formula if the coordinates are known.
You can use the Pythagorean Theorem for this one. In other words, calculate square root of (difference-of-x-coordinates squared + difference-of-y-coordinates squared).
-24.046464, 135.864256