2,4,8,16,32,64,128,256,512, 1024
4309 * 10^-3 4*10^0 + 3*10^-1 + 0*10^-2 + 9*10^-3
find the derivative of 3 -- 6 x + 10 x + 1000= 2 --18 x + 10 3&2 above xes are powers
5 x 10^3 + 2 x 10^2 + 8 x 10^1
quadrillion is a contraction of quad-million; to expand it into full, it depends upon where you are and which scale you are using. * In countries that use the long scale (based on powers of a million) like Europe: 3 quadrillion = 3 × (10^6)^4 = 3 × 10^24 = 3,000,000,000,000,000,000,000,000 * In countries that use the short scale (based on powers of a thousand plus one) like USA: 3 quadrillion = 3 × (10^3)^(4+1) = 3 × 10^15 = 3,000,000,000,000,000
2,4,8,16,32,64,128,256,512, 1024
To multiply powers with the same base, you add the exponents. For example, 10^2 x 10^3 = 10^5. Similarly, to divide powers with the same base, you subtract the exponents. For example, 10^3 / 10^5 = 10^(-2).
4309 * 10^-3 4*10^0 + 3*10^-1 + 0*10^-2 + 9*10^-3
powers are exponents. ten to the zero power=100=1 ten to the first power=101=10 ten to the second power=102=100 etc.
81.402 in expanded form using the powers of ten = (8 x 10^1) + (1 x 10^0) + (4/10^1) + (0/10^2) + (2/10^3)
The sum of the first 10 multiples of 3 is 165.
find the derivative of 3 -- 6 x + 10 x + 1000= 2 --18 x + 10 3&2 above xes are powers
5 x 10^3 + 2 x 10^2 + 8 x 10^1
0.1 These are all powers of 10: 10^3 = 1000 10^2 = 100 10^1 = 10 10^0 = 1 10^-1 = 0.1
quadrillion is a contraction of quad-million; to expand it into full, it depends upon where you are and which scale you are using. * In countries that use the long scale (based on powers of a million) like Europe: 3 quadrillion = 3 × (10^6)^4 = 3 × 10^24 = 3,000,000,000,000,000,000,000,000 * In countries that use the short scale (based on powers of a thousand plus one) like USA: 3 quadrillion = 3 × (10^3)^(4+1) = 3 × 10^15 = 3,000,000,000,000,000
3,264 = (3 x 10^4) + (0 x 10^3) + (2 x 10^2) + (6 x 10^1) + (4 x 10^0)
The closest you can get by: Using Each Number Once With Powers: 10 th the second power - 4 th the third power=46 Using each Number Once Without Powers:(4*10)-3+2 Using an indefinite amount of each number:4-*10+(3*2)-(2+2+2)