4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32
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For 4 It's 1,2,4 For 6 1,2,3,6 For 8 1,2,4,8
3, 6, 9, 12.
The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.
Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.