4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32
For 4 It's 1,2,4 For 6 1,2,3,6 For 8 1,2,4,8
3, 6, 9, 12.
The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
Multiples of 6: 1,2,3,6 Multiples of 4: 1,2,4 Multiples of 3: 1,3
The first 6 multiples of 4 are: 4, 8, 12, 16, 20, and 24.
2, 4, 6, 8.
6,12,18,26 they are the first four multiples of six
For 4 It's 1,2,4 For 6 1,2,3,6 For 8 1,2,4,8
3, 6, 9, and 12 are the first four integer multiples (products of 1, 2, 3, 4). 6, 9, 12, and 15 are the first four prime multiples (products of 2, 3, 4, 5).
3, 6, 9, 12, 15, 18 4, 8, 12, 16, 20, 24 6, 12, 18, 24, 30, 36 Common multiples include 12, 24, 36, 48, 60, 72
If ordered by size, only every other multiple of 2 is a multiple of 4. All multiples of 4 are multiples of 2.
the first six multiples of 4 are 4,8,12,16,20,24
Multiples of 6:6*1=66*2=126*3=186*4=24
6, 12, 18, 24
2, 4, 6, 8.
3, 6, 9, 12.