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To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
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What is the sum of the first 4 multiples of 5?
5 + 10+15+20=50 ans
What is the sum of the first 2 multiples of 6?
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
What is the sum of the first five multiples of 6?
6+12+18+24+30=90
What is the first 2 common multiples of each pair of numbers 4 and 6?
The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.
4 times the sum of a number and 6?
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
