To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
5 + 10+15+20=50 ans
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
The first 6 multiples of 9 are 9, 18, 27, 36, 45 and 54. Their sum (total) is 189. In other words, 1x9 + 2x9 + 3x9 + 4x9 + 5x9 + 6x9 = 21x9 = 189.
The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.
5 + 10+15+20=50 ans
90
It is: 6+12+18 = 36
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
the first six multiples of 4 are 4,8,12,16,20,24
6+12+18+24+30=90
The first 6 multiples of 4 are: 4, 8, 12, 16, 20, and 24.
The first 6 multiples of 9 are 9, 18, 27, 36, 45 and 54. Their sum (total) is 189. In other words, 1x9 + 2x9 + 3x9 + 4x9 + 5x9 + 6x9 = 21x9 = 189.
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
The first 10 multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, and 40.The first 10 multiples of 6 are: 6, 12, 18, 24, 30, 36, 42, 48, 54, and 60.