To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
5 + 10+15+20=50 ans
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
6+12+18+24+30=90
The first two common multiples of the pair of numbers 4 and 6 are: 12, 24.
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
5 + 10+15+20=50 ans
90
It is: 6+12+18 = 36
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
the first six multiples of 4 are 4,8,12,16,20,24
6+12+18+24+30=90
The first 6 multiples of 4 are: 4, 8, 12, 16, 20, and 24.
Well, isn't that a happy little question! To find the sum of the first 6 multiples of 9, you simply add them all together. So, 9 + 18 + 27 + 36 + 45 + 54 equals 189. Just like painting a beautiful landscape, math can be a peaceful and rewarding experience.
It is 751500.Here's the first ten.6, 12, 18, 24, 30, 36, 42, 48, 54, 60
The first 10 multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, and 40.The first 10 multiples of 6 are: 6, 12, 18, 24, 30, 36, 42, 48, 54, and 60.