the answer is 49
Oh, dude, the Highest Common Factor (HCF) of 441 and 630 is like the biggest number that can divide both of them without leaving a remainder. So, you just gotta find the common factors of 441 and 630, and the highest one is gonna be your HCF. It's like finding out which friend can evenly split the last slice of pizza with you and your buddy.
70, 140, 210, 280, 350, 420, 490, 560, 630, 700, 770 and just keep adding 70 until you get to infinity.
The first 10 multiples of 70: 70, 140, 210, 280, 350, 420, 490, 560, 630, 700
The first 15 multiples of 70: 70, 140, 210, 280, 350, 420, 490, 560, 630, 700, 770, 840, 910, 980, 1050 . . .
the answer is 49
70
70
Oh, dude, the Highest Common Factor (HCF) of 490 and 1050 is 70. It's like the cool kid that hangs out with both 490 and 1050 without any drama. So, yeah, 70 is the number that divides both 490 and 1050 without leaving any remainder.
Looks like 70, 490 = 7 x 70, 630 = 9 x 70 and 7 and 9 are co-prime.
HCF(140, 490) = 70 So 70 and any factor of 70 will do.
Well, isn't that a happy little question! The Highest Common Factor (HCF) of 540 and 630 is 90. You see, the HCF is the largest number that divides both 540 and 630 evenly, like a gentle brushstroke connecting two beautiful mountains.
You don't. You need at least two numbers to find a GCF.
The Highest Common Factor is 126
LCM of two numbers is their product divided by their HCF. First find HCF: 462 = 2 x 3 x 7 x 11; 630 = 2 x 3 x 3 x 5 x 7. The common factors are 2 x 3 x 7 ie HCF = 42 LCM is therefore 462 x 630 / 42 ie 11 x 630 = 6930
hcf(490, 1750) = 70 Using factorisation: 490 = 2 x 5 x 7² 1750 = 2 x 5³ x 7 hcf = 2 x 5 x 7 = 70
The number is 490.