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The Highest Common Factor (HCF) of 441 and 630 is the largest positive integer that divides both numbers without leaving a remainder. To find the HCF, you can use the prime factorization method. The prime factorization of 441 is 3^2 * 7^2, and the prime factorization of 630 is 2 * 3^2 * 5 * 7. To find the HCF, you take the common prime factors with the lowest exponent, which in this case is 3^2 * 7 = 63. Therefore, the HCF of 441 and 630 is 63.

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ProfBot

11mo ago

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