First, you need to know the formula for the area of a triangle: A = (1/2)bh, where b is the base and h is the height. Second, the word problem tells you something about the length of the base in terms of the length of the height. Since the base is two feet less than the height, we can write b = h - 2. Third, substitute: A = (1/2)bh = (1/2)(h-2)h = (1/2)h2 - h. Since the area is 12, we have 12 = (1/2)h2 - h. Fourth, rewrite the equation in standard form. (It's a quadratic equation.) Subtracting 12 from both sides of the equation, we get (1/2)h2 - h - 12 = 0, which is not quite there yet. Multiply both sides of the equation by 2 to get h2 - 2h - 24 = 0. Last, factor. You can easily factor that equation in your head; you need not use the quadratic formula. Here it is: (h-6)(h+4) = 0. So, you get h = 6, and h = -4. Since the length can't be negative, we discard the -4. We know, therefore, the height of the triangle is 6. Since b = a - 2, then b = 6 - 2 = 4.
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
30 square inches. Area of triangle = (base x height) divided by 2.
If you are only given the side lengths of a scalene triangle, it is impossible for you to find for the area, unless you are given more information... like the height of the triangle for example. If this is a right triangle you would like to find the area of, you can multiply the length of each leg with each other, and then divide that product by 2 to conclude the area of the triangle.
Ok to find the area of an isosceles triangle: Find the height first, to do this use this formula: Height = Square root ( one side square - half the base square) Now that you have the height you can calculate the area by the use of this formula: Area = (1/2)(base)(height) This will give you the surface area of an isosceles triangle. Lets do an example: You have a triangle that has two sides that measure 24 meters and a base of 20 meters. Using the formula above for height you will get a height of 21.8 meters Now use the formula above to find the area and it will give you an area of 218 meters square
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
What is 12 in ? And what is 16 in ? ? Are they the lengths of two sides of the triangle ? Are they the length of one side and the height of the triangle ? The area of any triangle is 1/2 of the product of (length of its base) x (its height).
The area of any triangle is: 0.5*base*perpendicular height
the height of a triangle is three feet longer than the base. The area of the triangle is 35 square feet. Find the height andbase of the triangle
Square feet is a measure of area and does not have to be square. The area of a triangle is 0.5*base*height where the base and height are expressed in feet. (The height is the vertical distance from the apex t the base.)
If you only have the triangle's area, then you only know the product of (base times height) ... it's double the area ... but you can't tell what either of those individual lengths is.
Area of a triangle = 1/2*base*height Area = 14 square inches
A triangle is half a square The area of a square is height × width(base) So, the area of a triangle is height × base ÷ 2 5×4÷2 = 10
Area triangle = 1/2 base x height Area square = length x width = 10in x 10in = 100sq in. Area triangle = area square Therefore: 1/2 x 10in x height = 100sq in height = 100 sq in x 2 / 10 in = 20 in
You do not indicate if the given area is the total area of the square and the triangle. Or whether they are equal values.
area of any triangle is 1/2 x base x height.
Area of a triangle in square units = 0.5*base*height
Area of a triangle in square units = 0.5*base*height