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First, you need to know the formula for the area of a triangle: A = (1/2)bh, where b is the base and h is the height. Second, the word problem tells you something about the length of the base in terms of the length of the height. Since the base is two feet less than the height, we can write b = h - 2. Third, substitute: A = (1/2)bh = (1/2)(h-2)h = (1/2)h2 - h. Since the area is 12, we have 12 = (1/2)h2 - h. Fourth, rewrite the equation in standard form. (It's a quadratic equation.) Subtracting 12 from both sides of the equation, we get (1/2)h2 - h - 12 = 0, which is not quite there yet. Multiply both sides of the equation by 2 to get h2 - 2h - 24 = 0. Last, factor. You can easily factor that equation in your head; you need not use the quadratic formula. Here it is: (h-6)(h+4) = 0. So, you get h = 6, and h = -4. Since the length can't be negative, we discard the -4. We know, therefore, the height of the triangle is 6. Since b = a - 2, then b = 6 - 2 = 4.

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Q: What are the lengths of the base and the height of a triangle if its base is two feet less than its height and its area is 12 square feet?
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