114
This is called "square" sequence.144 = 122121 = 11264 = 8249 = 72Thus the missing numbers are 92 and 102 which are 81 and 100
Ascending terms in the sequence are equal to 12, 32, 52, __, 92, and, for some reason, 102, not 112. Therefore, assuming the last term in the sequence to be 112 = 121, the fourth term in the sequence is 72 = 49.
24, 25, 26, 27 (next to each other and add up to 102)
The two numbers would be 102 and 104. (102+104=206)
102
This is called "square" sequence.144 = 122121 = 11264 = 8249 = 72Thus the missing numbers are 92 and 102 which are 81 and 100
63, 102, 165...
110
Ascending terms in the sequence are equal to 12, 32, 52, __, 92, and, for some reason, 102, not 112. Therefore, assuming the last term in the sequence to be 112 = 121, the fourth term in the sequence is 72 = 49.
24, 25, 26, 27 (next to each other and add up to 102)
The next series in the pattern would start at 102 + 666. the pattern is +6, +66, and, presumably, +666. If the pattern were to hold true and continue it should be 768, 769, 770, 771, 772, 773, 774 that is a total of 6 numbers before the next series in the pattern and then 774 + 6666 for 4 numbers... the sequence for the pattern is 2, 5, 3, 6, 4, 7,...
The next number is 54. The sequence is generated by the rule: Un = (n4 - 11n3 + 51n2 - 107n + 102)/4 for n = 1, 2, 3, ... and U6 = 54.
Answer: 144, 169, 225 Explanation: 72=49, 92=81, similarly 102=100, 122=144
There are no two consecutive numbers that add or multiply to 102.
103, 104, 105 * * * * * Probably not 105, because the rest form the sequence 18 to 29, in base 10, expressed as base 5 numbers. If so, 104 would be followed by 110, 111, 112, ...
There are 27 prime numbers less than 102.
The prime numbers between 102 and 113 are 103, 107, and 109.