The next number is 54.
The sequence is generated by the rule:
Un = (n4 - 11n3 + 51n2 - 107n + 102)/4 for n = 1, 2, 3, ... and U6 = 54.
103, 104, 105 * * * * * Probably not 105, because the rest form the sequence 18 to 29, in base 10, expressed as base 5 numbers. If so, 104 would be followed by 110, 111, 112, ...
321
t(n) = t(n - 1) + (10n - 9)
105
105 1st number is 13 = 1 2nd number is 23 = 8 3rd number is 33 = 27 So, 4th number is 43 = 256
When counting by 5's, the next number after 100 would be 105. This is because you are adding 5 to each subsequent number in the sequence. Therefore, after 100, the next number in the sequence would be 105.
110
The whole number that comes right before 105 is 104. Whole numbers are the set of numbers starting from 0 and increasing by 1 without any decimals or fractions. In this sequence, the number before 105 is 104, as it is the whole number that is one less than 105.
The pattern is: +11, +15, +19, +23, +27 (4n+7) So, the next number would be: (4*6 + 7) = 24 + 7 = +31 Therefore, the answer is: 105 + 31 = 136
In the sequence 35, 70, 105, 140, 175, each number is the previous number plus 35.
The answer is 67 because the pattern is 2x(x-1)-3 11-7 is 4 19-11 is 8 which is twice 4 35-19 is 16 which is twice 8 so the next difference is twice 16, =32 so the next number is 35+32 =67
103, 104, 105 * * * * * Probably not 105, because the rest form the sequence 18 to 29, in base 10, expressed as base 5 numbers. If so, 104 would be followed by 110, 111, 112, ...
In integers, 104
105 years
It is possible to select a polynomial of order 4 so that any number can be next. However, there is only one polynomial of degree three that will fit the four points:Un = (-53n3 + 375n2 - 778n + 510)/6 for n = 1, 2, 3, ...and according to that rule, the next number, U5 = -105.
105 Because it is over a half or .5 it is rounded up to the next whole number.
321