103, 104, 105 * * * * * Probably not 105, because the rest form the sequence 18 to 29, in base 10, expressed as base 5 numbers. If so, 104 would be followed by 110, 111, 112, ...
321
t(n) = t(n - 1) + (10n - 9)
105
105 1st number is 13 = 1 2nd number is 23 = 8 3rd number is 33 = 27 So, 4th number is 43 = 256
110
The pattern is: +11, +15, +19, +23, +27 (4n+7) So, the next number would be: (4*6 + 7) = 24 + 7 = +31 Therefore, the answer is: 105 + 31 = 136
In the sequence 35, 70, 105, 140, 175, each number is the previous number plus 35.
The answer is 67 because the pattern is 2x(x-1)-3 11-7 is 4 19-11 is 8 which is twice 4 35-19 is 16 which is twice 8 so the next difference is twice 16, =32 so the next number is 35+32 =67
105
103, 104, 105 * * * * * Probably not 105, because the rest form the sequence 18 to 29, in base 10, expressed as base 5 numbers. If so, 104 would be followed by 110, 111, 112, ...
In integers, 104
It is 104.
105 years
It is possible to select a polynomial of order 4 so that any number can be next. However, there is only one polynomial of degree three that will fit the four points:Un = (-53n3 + 375n2 - 778n + 510)/6 for n = 1, 2, 3, ...and according to that rule, the next number, U5 = -105.
105 Because it is over a half or .5 it is rounded up to the next whole number.
321