A 1 in 36 chance
The above is not true, though I can understand why this mistake might be made, for example,
if you have 1 die, then your chances of rolling any given number are 1/6, multiply this by six die and you get 1/36 RIGHT?
What actually happens is more complicated.
Imagine you are holding 1 die and want to roll a 5, you have a 1/6 chance to do this.
Now take a second die, assuming you rolled a 5 on the first, you have a 1/6 chance of rolling a second 5, so the total odds that you can roll a pair of fives is actually 1/6*1/6 = 1/36. If you add another die, you have to then multiply this by 1/6 and so on.
Extend this to having six die and it continues:
5 on 1 die =1/6
5 on 2 die =1/6*1/6=1/36
5 on 3 die =1/6*1/6*1/6=1/216
5 on 4 die =1/6*1/6*1/6*1/6=1/1296
5 on 5 die =1/6*1/6*1/6*1/6*1/6=1/7776
5 on 6 die =1/6*1/6*1/6*1/6*1/6*1/6=1/46656
Now to complicate matters, if you want to roll six 5's your chances are 1/46656
HOWEVER, if you don't care what your six of a kind is, then essentially the "first" die doesn't matter in the calculations, it's just there to determine what number we are after, leaving us with a total of five "more" die the we need to get that number on.
So if you just want to roll "SIX OF A KIND" and don't care what number it is, your chances are 1/7776
The probability of rolling a 3 or 4 with a 6 sided die is 2 over 6. Also known as one/third.
If the faces on the 12 sided die are numbered from 1 to 12, then 1/12.
assuming a single six sided die the probability of rolling a three is 1/6
Six.
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
One in Six
on a 6-sided die theres a 1/6 chance
0.54 or 0.0625
The odds of rolling a single one on a 20-sided die is 1 in 20 (1/20). Since the rolls are independent events, the odds of rolling two ones on two 20-sided dice would be (1/20) * (1/20), which simplifies to 1 in 400 (1/400).
If it's a six-sided die (like the kind used in craps and most dice games) the odds are 1 in 6.The probability of rolling a single number on any kind of die* is 1 ÷ (the number of sides).*Except, of course, for weighted, shaved, or otherwise illegal dice.
Assuming they are six sided die then the probability is 1 out of thirty six
Assuming that there is only one 1 on the 100 faces, the odds are (1/100)3 or 10-6, that is 1 in a million.
Since there are six sides on a die, the odds of rolling a 4, or any digit for that matter is 1/6
0.5
if you rollid a die once the odds of getting less than four would be 3/6 or 50%.
The probability of rolling a 6 on a standard six-sided die is 1 out of 6, or approximately 16.67.
The chances of rolling three consecutive numbers on a six-sided die are 1 in 216.