One in Six
-3
Odds of rolling ONE six - 6:1 Odds of rolling TWO sixes - 36:1 Odds of rolling two sixes, SIX times - 216:1
It's deduction. You can find the odds of something happening by first finding out the odds of that something not happening. That is converse probability. For instance the odds of rolling a "3" on a 6 sided die. Using converse probability would be 5/6 (5 sides are not the number "3"). 6/6 (six sides in all) - 5/6 = 1/6 is the odds of rolling that "3".
One in every three.
Well I'm supposing it's a 6 sided dye. Since there are 6 sides it's a 1 out of 6 chance or 16% chance that you would roll a 4.The odds against rolling a 4, the complementary event, are 5 out of 6, a chanceof: 1 - 0.1666.. = 0.8333... ≈ 83.3%.
i am not sure
0.54 or 0.0625
The odds of rolling a specific number on a six-sided dice are 1 in 6.
Assuming they are six sided die then the probability is 1 out of thirty six
-3
The odds of rolling a word with the keyword "dice" on each side of a standard six-sided dice is 1 in 46,656.
1/6 x 1/6 x 1/6 = 1/216 is the odds of getting three doubles in a row so I suppose the odds of not rolling three in a row is 215/216 or 99.54% chance.
Assuming that there is only one 1 on the 100 faces, the odds are (1/100)3 or 10-6, that is 1 in a million.
The odds of rolling a single one on a 20-sided die is 1 in 20 (1/20). Since the rolls are independent events, the odds of rolling two ones on two 20-sided dice would be (1/20) * (1/20), which simplifies to 1 in 400 (1/400).
2 out of 12
if you rollid a die once the odds of getting less than four would be 3/6 or 50%.
on a 6-sided die theres a 1/6 chance