True * * * * * No. The only regular polygons that will tessellate are a triangle, a square and a heagon. So a regular heptagon will not tessellate.
noX YES! They CAN tessellate! Triangles, squares, and hexagons are the only shapes that can tessellate by themselves! So yes, squares can tesselate!
In mathematical logic, An integer A if divisible by 100 iff the last two digits are 0. "iff" stands for "if and only if".
yes... this figure does tessellate
No it does not tessellate you have to pentagons in order for it to tessellate. * * * * * It is not at all clear what "have to pentagons" has to do with this. No polygon with 7 or more sides will tessellate. Octagons will tessellate if mixed with squares but that is not "proper" tessellation since it involved more than one shape.
True * * * * * No. The only regular polygons that will tessellate are a triangle, a square and a heagon. So a regular heptagon will not tessellate.
how is it possible that modern computer systems rely on only two digits?
noX YES! They CAN tessellate! Triangles, squares, and hexagons are the only shapes that can tessellate by themselves! So yes, squares can tesselate!
Binary digits are 'bits'. There are only two of them. It doesn't matter what you call your digits or how you write them, as long as you do all of your binary arithmetic with only two symbols.
It will tessellate if its vertices divide into 360 degrees evenly. The only regular polygons that will tessellate are an equilateral triangle, a square and a regular hexagon. There are other, non-regular, polygons that will tessellate.
Mostly true - you cannot tessellate only regular pentagons in two dimensions, since you cannot sum up the intersection of the angles to 360 degrees. If you tessellate a regular pentagon in three dimensions, you end up with a dodecahedron.
Any polygon with external angles which are equal to a factor of 360 will tessellate. The only regular polygons which will tessellate are equilateral triangles, squares, and hexagons.
No, only some can.
I believe that regular shapes will only tessellate if the sum of their internal angles is a multiple of 180.
Not all shapes can tessellate. For example a pentagon will not tessellate. Only those shapes where the angles of the vertices which meet sum to 360° (a full turn) will tessellate. For example, with a regular hexagon, each angle is 120° and when three come together they form 3×120° = 360° and so will tessellate, but with an octagon, each angle is 135°; two such angles form 2×135° = 270°, but three such angles form 3×135° = 405° - two octagons will lay together with a gap, but three octagons will overlap: they cannot tessellate; however, 360° - 270° = 90° which is the angle of a square, so octagons together with squares will tessellate.
No because only polygons whose interior angles are a factor of 360 will tessellate. For instance a regular pentagon will not tessellate because its interior angle is 108 degrees but a hexagon will tessellate because its interior angle is 120 degrees which is a factor of 360.
When using significant digits, the product has only the number of significant digits as the lowest number in the factors. "20" has two significant digits and "310" has three. Therefore, the product has to have two significant digits. 310 × 20 = 6200 6200 already has two significant digits.