89 x 20 = 1780
89 x 5 = 445
80 x 20 = 1600
9 x 20 = 180
80 x 5 = 400
9 x 5 = 45
80*6, 9*6
how to find the partial products of a number
700 and 210 are the answers to partial products of 77 times 30
29 x47=
Single digits don't have partial products. 8 x 6 = 48
89 x 20 = 1780 89 x 5 = 445 80 x 20 = 1600 9 x 20 = 180 80 x 5 = 400 9 x 5 = 45
80*6, 9*6
80 x 20 = 1600 80 x 5 = 400 20 x 9 = 180 5 x 9 = 45
how to find the partial products of a number
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
700 and 210 are the answers to partial products of 77 times 30
20 x 70 = 1400 5 x 70 = 350 3 x 20 = 60 3 x 5 = 15 25 x 73 = 1875
2,225
29 x47=
90 and 54
80 + 24
32 and 160