The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
4 x 40 = 160 4 x 8 = 32 160 + 32 = 192 4 x 48 = 192
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
The product is 48
The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
Single digits don't have partial products. 8 x 6 = 48
4 x 40 = 160 4 x 8 = 32 160 + 32 = 192 4 x 48 = 192
80 + 24
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
how to find the partial products of a number
The partial products for 734X29 are 6,606 and 14,680.
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
Partial products of 87 times 65 would be 80 x 60 and 80 x 5 and 7 x 60 and 7 x 5. Partial products allow for the multiplication of whole numbers.
30 x 20 = 600 30 x 8 = 240 4 x 20 = 80 4 x 8 = 32
700 and 210 are the answers to partial products of 77 times 30
300 x 40 = 12000 300 x 8 = 2400 50 x 40 = 2000 50 x 8 = 400 7 x 40 = 280 7 x 8 = 56