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If: y = x2-7x+8 and y = -x2+9x-6

Then: x2-7x+8 = -x2+9x-6

So: 2x2-16x+14 = 0 => x2-8x+7 = 0

Therefore: x = 1 and x = 7

By substitution: x =1, y = 2 and x = 7, y = 8

Points of intersection: (1, 2) and (7, 8)

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