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There are two kinds of incomplete quadratic equations:
1) ax2+bx=0 (e.g. 4x2+2x=0)
2) ax2+c=0 (e.g. 5x2-125=0)
And the ways to solve them are as follows:
Type 1) For example, 4x2+2x=0.
You take out x (and a number multiplying it, if possible:)
2x(2x+1)=0
In order for the equation to be correct, then either the outcome of the brackets (2x+1) or the number multiplying them (2x) needs to be zero:
2x+1=0
2x=-1
x1=-0.5
2x=0
x2=0
So the two solutions are -0.5 and 0. This also works if you take out only x:
x(4x+2)=0
4x+2=0
4x=-2
x1=-0.5
x2=0
Type 2) For example, 5x2-125=0. This type of incomplete quadratic equation can be solved like a regular equation, as follows:
5x2-125=0
5x2=125
x2=25
x=±5 (x1=5, x2=-5)
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