Find three consecutive positive even integers whose sum is 123 , Answer
The numbers are 39, 41 and 43.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
189/3 = 63 So the three odd integers are 61, 63 and 65
They are: -39 -41 -43 = -123
123/3 = 41 so integers are 39, 41 and 43
Find three consecutive positive even integers whose sum is 123 , Answer
The numbers are 39, 41 and 43.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
For three consecutive odd integers to have the sum 123, the equation N + N+2 + N+4 = 123 must be solvable with N being an odd integer.N + N+2 + N+4 = 1233N + 6 = 1233N = 117N = 39Since 39 is an odd integer, the solution is 39, 41, and 43.If N were even, or if N resolved to a non-integer, then the problem would have been incorrectly stated and unsolvable.
39,41,43! Ya
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.
Those three odd integers are 43, 45, and 47.
189/3 = 63 So the three odd integers are 61, 63 and 65