This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
There are 128 integers between 100 and 1000 that are divisible by seven.
We're not sure exactly what the question is looking for, so I made upmy own, and it leads to a fascinating investigation. I hope this is actuallywhat the questioner has in mind.The question seems to be asking: "Find seven consecutive numbers that areall composite."I did a quick investigation, and found some neat stuff. I sure hope my method was valid.-- There actually is a string of seven composite numbers less than 100.They are: 90, 91, 92, 93, 94, 95, 96.-- There are seven strings of five consecutive composite numbers, all less than 100.-- The next series of seven consecutive composites doesn't occur until 360-366.But on the way there, there are five strings of 9 composites, two strings of 11 composites,and three strings of 13 composites.-- There are no series of an even number of consecutive composites, at leastnot up to 200,000 . Wonder why that is.-- The string of 19 consecutive numbers from 888 to 906 are all composite.-- Up to 200,000, the grand-daddy is the range from 155,922 to 156,006 ...a series of 85 consecutive integers that are all composite.
They are seven, eight, and nine. Hint, letting m be the middle number, 9m will be close to 74. Further hint, 2(m - 1) + 3m + 4(m + 1) = 2m - 2 + 3m + 4m + 4 = 9m + 2. Thus, the middle integer must be 8. Three consecutive integers are such thatwhen they are taken in increasing order and multiplied by 23 and 4 respectivelythey add up to 74 find these numbers?
108 109 110 111 112 113 114
The smallest of seven consecutive even integers whose sum is 700 is 94.
The LCM of consecutive integers is their product. Consecutive integers will not both be multiples of seven.
Six and seven
leggoos
21 17+19+21 =57
The smallest six consecutive composite integers are:90, 91, 92, 93, 94, 95.(And 96 is also composite, for a run of seven consecutive.)Is that what you were asking ?
Let first odd number be 2n + 1 The next odd number is 2n + 3 Hence 7*(2n +1) = 5*(2n + 3) 14n + 7 = 10n + 15 14n - 10n = 15 - 7 4n = 8 n = 2 Verify that 7*5 = 5*7 or 35 = 35, hence the numbers are 5 and 7
Let's represent the three consecutive odd integers as ( 2n-1 ), ( 2n+1 ), and ( 2n+3 ), where ( n ) is an integer. According to the given information, twice the smallest integer ( 2(2n-1) ) is equal to seven more than the largest integer ( 2n+3 ). Setting up the equation, we have ( 4n-2 = 2n+3+7 ). Solving this equation gives us ( n = 6 ). Therefore, the three consecutive odd integers are 11, 13, and 15.
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
It is a negative integer. Its value will depend on the seven integers that you start with.
There are 128 integers between 100 and 1000 that are divisible by seven.
One and seven.