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Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
Let's represent the three consecutive odd integers as ( 2n-1 ), ( 2n+1 ), and ( 2n+3 ), where ( n ) is an integer. According to the given information, twice the smallest integer ( 2(2n-1) ) is equal to seven more than the largest integer ( 2n+3 ). Setting up the equation, we have ( 4n-2 = 2n+3+7 ). Solving this equation gives us ( n = 6 ). Therefore, the three consecutive odd integers are 11, 13, and 15.
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Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91?
98
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
Twice the sum of two consecutive integers is 246?
2 [ x + (x+1) ] = 246x + (x+1) = 1232x + 1 = 1232x = 122x = 61x+1 = 62ho hum
How do you find three consecutive integers so that twice the first increased by three times the third will be -24?
The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
