Answer: 11, 12, 13 or -13, -12, -11
Details:
Assume the numbers are: n-1, n, n+1 ...... (1)
then, (n-1)2 + n2 + (n+1)2 = 434
3n2 + 2 = 434
3n2 = 432
n2 = 144
n = 12 or -12
substitute in eq 1
the answer is:
11, 12, 13
or
-13, -12, - 11
They are palindromic.
There are 9 palindromic numbers between 400 and 500. A palindromic number reads the same forwards and backwards. The palindromic numbers in this range are 404, 414, 424, 434, 444, 454, 464, 474, and 484.
217
1026 - 434 = 592
It is: 434/7 = 62
They are palindromic.
434 is an even number, so it is obviously not prime and therefore composite.
1 x 434, 2 x 217, 7 x 62, 14 x 31
430
Three-Hundred and Fifty-Two
15% of 434= 15% * 434= 0.15 * 434= 65.1
85% of 434 = 85% * 434 = 0.85 * 434 = 368.9
It is a composite number. It is an even number, so it is divisible by 2. The only even number that is a prime number is 2. All other even numbers are composite numbers.
There are an infinite amount of answers to that, like: 430 + 4 = 434 400.5 + 33.5 = 434 202 + 232 = 434
Simply multiply the numbers together: 434 sq ft
No, 434 is not a prime number because...1 x 434 = 4342 x 217 = 434
56/4 238/17 434/31