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Answer: 11, 12, 13 or -13, -12, -11

Details:

Assume the numbers are: n-1, n, n+1 ...... (1)

then, (n-1)2 + n2 + (n+1)2 = 434

3n2 + 2 = 434

3n2 = 432

n2 = 144

n = 12 or -12

substitute in eq 1

the answer is:

11, 12, 13
or
-13, -12, - 11

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Q: What are three consecutive numbers the sum of their squares is 434?
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