The numbers are 76 23 45
The numbers are -169, -168 and -167.
√144 < √165 < √169 12 < √165 < 13
169 can be divided by: 1, 13, 169.
There are two consecutive odd integers whose sum is 340. They are 169 and 171.
171
Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their cubes can be expressed as ( (n + 1)^3 - n^3 ). Simplifying this gives ( 3n^2 + 3n + 1 ). Setting this equal to 169, we have the equation ( 3n^2 + 3n + 1 = 169 ). Solving for ( n ) yields ( n^2 + n - 56 = 0 ), which factors to ( (n - 7)(n + 8) = 0 ). Thus, ( n = 7 ) (ignoring ( n = -8 ) since we want positive consecutive numbers), giving the two consecutive numbers as 7 and 8.
There is no set of four consecutive numbers (odd or even) whose sum equals 169.
The numbers are -169, -168 and -167.
The numbers are 167, 168 and 169.
169 = 144 + 25, so your numbers are 12 & 5.
168 and 169
√144 < √165 < √169 12 < √165 < 13
169 can be divided by: 1, 13, 169.
The divisors of 169 are 1, 13, and 169.
504 / 3 = 168 then add 1 on and take 1 off so 167 + 168 + 169 = 504
There are two consecutive odd integers whose sum is 340. They are 169 and 171.
between 12 and 13 (144 and 169)