Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their cubes can be expressed as ( (n + 1)^3 - n^3 ). Simplifying this gives ( 3n^2 + 3n + 1 ). Setting this equal to 169, we have the equation ( 3n^2 + 3n + 1 = 169 ). Solving for ( n ) yields ( n^2 + n - 56 = 0 ), which factors to ( (n - 7)(n + 8) = 0 ). Thus, ( n = 7 ) (ignoring ( n = -8 ) since we want positive consecutive numbers), giving the two consecutive numbers as 7 and 8.
8 and 9
Let the two consecutive numbers be ( n ) and ( n+1 ). The difference of their cubes can be expressed as ( (n+1)^3 - n^3 = 3n^2 + 3n + 1 ). Setting this equal to 631 gives the equation ( 3n^2 + 3n + 1 = 631 ). Solving for ( n ) leads to ( 3n^2 + 3n - 630 = 0 ), which simplifies to ( n^2 + n - 210 = 0 ). Factoring or using the quadratic formula, we find ( n = 14 ) or ( n = -15 ). Therefore, the consecutive numbers are 14 and 15.
Consecutive numbers are whole numbers whose difference is 1.
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
8 and 9
8 and 9
8
62 and 63
15 and 16
Consecutive numbers are whole numbers whose difference is 1.
There are two consecutive even numbers. The numbers are 62 and 64.
Any pair of consecutive numbers will have an odd total. 10 and 12 are consecutive even numbers that total 22.
24 and 25, which are (49-1)/2 and (49+1)/2
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
The numbers are 64 and 65.
The numbers are -8, and -7.