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Let the two consecutive numbers be ( n ) and ( n + 1 ). The difference of their cubes can be expressed as ( (n + 1)^3 - n^3 ). Simplifying this gives ( 3n^2 + 3n + 1 ). Setting this equal to 169, we have the equation ( 3n^2 + 3n + 1 = 169 ). Solving for ( n ) yields ( n^2 + n - 56 = 0 ), which factors to ( (n - 7)(n + 8) = 0 ). Thus, ( n = 7 ) (ignoring ( n = -8 ) since we want positive consecutive numbers), giving the two consecutive numbers as 7 and 8.

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AnswerBot

2w ago

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