There are none. Two odd numbers added together equal a even number.
Yes, if the number whose square root we are taking is greater than 0. Only if you try to take the square root of a negative number will you get back an imaginary number. Square roots are often irrational, but that's different from real versus imaginary.
There's only one number that's equal to 80. It's 80.There's a good chance that there could be three numbers whose sum is 80, or threedifferent numbers whose joint product is 80, but the question doesn't ask for those.
It would be possible to find two numbers whose sum is 7, two others whose difference is 7,two others whose product is 7, and two others whose quotient is 7.But if you're looking for numbers that equal 7, then 7 is your only choice.
4.5 - 9.579i and 4.5 + 9.579i where i is the imaginary number which is the square root of -1
No, but it is irrational, because there is no rational number whose square is two. Imaginary numbers are the square roots of negative numbers.
Most famously, an imaginary number, that is, a number whose square (which is the number multiplied by itself) is negative. All real numbers have positive squares. A complex number, is a number which is the sum of a real number and an imaginary number, and so is also a non-real number.
There are an infinite number of groups of numbers whose sum, difference, product, quotient etc. is equal to 40 . But there are not four numbers that equal 40. In fact, there is only one number that equals 40. The number is . . . . . 40 .
Yes. And since Real numbers are a subset of complex numbers, a complex number can also be a pure real.Another AnswerYes, for example: (0 + j5) is a complex number, whose 'real' number is zero.
In mathematics, an imaginary number is a number whose square is a negative real number and written in the form bi where i is the imaginary number √(-1) and b is real.A complex number is a number with both real and imaginary numbers, such as (3+2i), where 3 is real and 2i is imaginary.Imaginary numbers were 'invented' by Gerolamo Cardano in the 1500's while solving cubic and quartic equations although it is said he did not understand their properties, and they were not properly defined until 1572 by Rafael Bombelli, although he did not name them imaginary numbers.The name came from Descartes in his book "La Geometrie" where it was meant to be derogatory and sarcastic, as the number √(-1) was thought not to exist by many mathematicians. It was not until the work of Euler in analysis that the imaginary number i was properly understood and widely acknowledged as being a proper numberAnother AnswerMathematicians call the horizontal and vertical axes of a graph, the 'real' and 'imaginary' axes. Numbers lying along the real (horizontal) axis are called 'real numbers', and numbers lying along the imaginary (vertical) axis are called 'imaginary numbers'.(see first discussion page entry)
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There are none. Two odd numbers added together equal a even number.
Imaginary numbers are numbers whose square is a negative number. They arose as a means of working with square roots of negative numbers; in fact, the first known mention of a square root of a negative number is a very brief one from a work called Stereometrica. It was written in the 1st century CE by a Greek mathematician, Heron of Alexandria. Imaginary (and thus, complex) numbers were not ever accepted widely, though, until the 1700s, because of the work of Euler and Gauss.
Yes, if the number whose square root we are taking is greater than 0. Only if you try to take the square root of a negative number will you get back an imaginary number. Square roots are often irrational, but that's different from real versus imaginary.
There is no real number whose square root can be negative so there is no real solution. So mathematicians invented the imaginary number i with the property that i*i = -1 i is fundamental to complex numbers.
There's only one number that's equal to 80. It's 80.There's a good chance that there could be three numbers whose sum is 80, or threedifferent numbers whose joint product is 80, but the question doesn't ask for those.
"i" is the square root of -1. Since there is no real number whose square is negative, i is an imaginary number.