To solve the equation "x - 13 = 15," you would add 13 to both sides of the equation to isolate the variable x. This results in x = 28, as 15 + 13 = 28. Therefore, the value of x that satisfies the equation is 28.
15 times (13 x 15 = 195)
15 and 10 are both factors of 30.
13.867 times or 13 with remainder 13.
The LCM of both numbers is 156
-13
9 and 13 both go into 117.
15 and 5 both go into every multiple of 15 .
To solve the equation "x - 13 = 15," you would add 13 to both sides of the equation to isolate the variable x. This results in x = 28, as 15 + 13 = 28. Therefore, the value of x that satisfies the equation is 28.
16 and 13 both go into any multiple of 208 .
Both 15 and 20 can go into 60, as they are both factors of that number.
15 times (13 x 15 = 195)
They both go into 90.
11 and 15 both go into 165. 165 is the LCM (Least Common Multiple) of 11 and 15.
1 13 is a prime number.
13 times 11 = 143.So they both go into any integral multiple of 143.
15 and 10 are both factors of 30.