Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.The given sequence can be generated using the following polynomial of order 4:U(n) = (103*n^4 - 1242*n^3 + 5201*n^2 - 8670*n + 4680)/24 for n= 1, 2, 3, ...and, accordingly, the next term is 213.
16
14 18 20
Think it's 30...then 20
3, -6, 12, 4, 20, 13, 27, 21, 33 -9, +18, -8, +16, -7, +14, -6, +12
To find the next number in the series 4, 8, 12, 20, we need to identify the pattern or rule governing the sequence. In this case, the pattern is that each number is the sum of the previous two numbers. 4 + 8 = 12, 8 + 12 = 20, and 12 + 20 = 32. Therefore, the next number in the series is 32.
The sequence changes by multiplying with different numbers: from 3 to -6 (* -2), -6 to 12 (* -2), 12 to 4 (* 0.33), and 4 to 20 (* 5). If we continue this pattern, 20 multiplied by 0.5 gives us 10. So, the next number is 10.
42
10
16
14 18 20
24
The pattern goes -1 x5 so the next number is 19x5 which is 95
Think it's 30...then 20
The next figure would be 21, followed by 11 & 10.
3, -6, 12, 4, 20, 13, 27, 21, 33 -9, +18, -8, +16, -7, +14, -6, +12
To find the next number in the series 4, 8, 12, 20, we need to identify the pattern or rule governing the sequence. In this case, the pattern is that each number is the sum of the previous two numbers. 4 + 8 = 12, 8 + 12 = 20, and 12 + 20 = 32. Therefore, the next number in the series is 32.
10