The rise is calculated as the horizontal run distance times the tangent of the angle (tan angle = rise/run). Since tan 1 degree is 0.0175 the rise is 100 x .0175 = 1.75 feet
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (40 ft × tan 50° × tan 30°)/(tan 50° - tan 30°) ≈ 44.80 ft
Angle A=opposite/adjacent shift tan Angle B=90-Angle A
Suppose the length of the shadow is s metres. Then tan(62 deg) = 45/S so that S = 45/tan(62 deg) = 45/1.88 (approx = 23.93 metres, approx.
You can calculate this on any scientific calculator. Those calculators don't usually have a special key for the cotangens, but this is the same as 1 / tan(68).
1.00
1.00
- tan 60
To get this answer, type in tan(28) in your calculator. It should come out to be about .532. Make sure your calculator is in Degree mode.
tan(30 deg) = 0.5774, approx.
tan(2.68510941890) = 0.0469 approx. tan(2.6851) gives the same result. The additional digits are in the angle are quite spurious.
The rise is calculated as the horizontal run distance times the tangent of the angle (tan angle = rise/run). Since tan 1 degree is 0.0175 the rise is 100 x .0175 = 1.75 feet
cot 32° = 1/(tan 32°) = 1/(0.6249) = 1.6003
23.7
The rise over the distance is equal to the tangent of the angle Since tan (1 degree) = .0174 then the rise is .0174x13 = 0.227 meters ( 227 mm)
The cotangent is the reciprocal of the tangent, so simply calculate, on your scientific calculator, 1 / tan(68).
try height = 4 x tan 35 degrees