Suppose the length of the shadow is s metres.
Then tan(62 deg) = 45/S so that S = 45/tan(62 deg) = 45/1.88 (approx
= 23.93 metres, approx.
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
36 degrees
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
You take 280 times 10 and then divide that by 14 which equals 200 ft.
If you mean the height of the building then it works out as 466.5063509 feet
Using trigonometry the angle of elevation is 77 degrees rounded to the nearest degree
116
To determine the height of a building based on the length of its shadow, we need to know the angle of elevation of the sun. Without that information, we can't calculate the exact height. However, if we assume a specific angle, we could use the tangent function in trigonometry to find the height. For example, if the angle were 45 degrees, the building would also be 42 meters tall.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
It is: 27.35 degrees rounded to two decimal places
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
36 degrees
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
It is: tan(52)*9 = 11.519 meters rounded to three decimal places
18.6 m/52.6 degrees tan= 14.2
Use the tangent ratio: 23*tan(23) = 9.762920773 Answer: 10 meters to the nearest meter