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How high is the building whose shadow 45 meters when the angle of elevation of the sun is 62 degree 30 degree?
Wiki User
∙ 11y ago
Suppose the length of the shadow is s metres.
Then tan(62 deg) = 45/S so that S = 45/tan(62 deg) = 45/1.88 (approx
= 23.93 metres, approx.
Wiki User
∙ 11y ago
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How tall is a building with a 73 ft shadow when elevation of the sun is 31 degrees?
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
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How tall is a building with a 73 ft shadow when elevation of the sun is 31 degrees?
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
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36 degrees
What is the angle of elevation of the sun with the ground when the pole 7.6 meters casts a shadow 6.1 meters long?
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
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If you also know its shadow then you can work out the angle of elevation
