Any one of the infinitely many numbers of the form 126*k where k is an integer.
Any multiple of 126.
Only 2 goes into both 18 and 14. The prime divisors of 14 are 2 and 7. The prime divisors of 18 are 2, 3, and 3. The only common divisor is 2.
7 and 8 both go into 56
126 ÷ 7 = 18
18 goes into 140 7 times.
7 with 4 remaining 130 - 4 = 126 = 18 x 7
2*9=18 7*9=63 9 will go into both 18 and 63
No, it does not.
18
x + 7 - 2x = 18 Combine the terms containing x: 7 - x = 18 Subtract 7 from both sides: -x = 11 Multiply both sides by -1 (or change the sign on both sides): x = -11
The GCF of 7 and 18 is 1 because 7 is a prime number and seven does not go into 18.
126/7= 1 7 56/ 7=8 18 x 7 = 126. Answer: 18 times
Twice but there is a remainder of four. or 18/7=2.571428571428571
The Least Common Multiple of 14 and 18 is 126.
7 and 8 both go into 56
You can divide both by 3. 18/ 21 = 6/7 6/7 is your answer.
Only 2 goes into both 18 and 14. The prime divisors of 14 are 2 and 7. The prime divisors of 18 are 2, 3, and 3. The only common divisor is 2.
126 ÷ 7 = 18