Any one of the infinitely many numbers of the form 126*k where k is an integer.
126 ÷ 7 = 18
Only 2 goes into both 18 and 14. The prime divisors of 14 are 2 and 7. The prime divisors of 18 are 2, 3, and 3. The only common divisor is 2.
18 times132 / 7 = 18.8571429
10 times, remainder 11
7 and 8 both go into 56
2*9=18 7*9=63 9 will go into both 18 and 63
No, 18 does not go into 7 evenly. When you divide 7 by 18, the result is 0 with a remainder of 7. In other words, 18 cannot be divided into 7 without having a leftover amount.
The GCF of 7 and 18 is 1 because 7 is a prime number and seven does not go into 18.
x + 7 - 2x = 18 Combine the terms containing x: 7 - x = 18 Subtract 7 from both sides: -x = 11 Multiply both sides by -1 (or change the sign on both sides): x = -11
Both 6 and 9 go into 18, which is their least common multiple (LCM). This means that 18 can be evenly divided by both numbers. Additionally, they both go into any multiple of 18, such as 36, 54, and so on.
Twice but there is a remainder of four. or 18/7=2.571428571428571
The Least Common Multiple of 14 and 18 is 126.
126 ÷ 7 = 18
You can divide both by 3. 18/ 21 = 6/7 6/7 is your answer.
Only 2 goes into both 18 and 14. The prime divisors of 14 are 2 and 7. The prime divisors of 18 are 2, 3, and 3. The only common divisor is 2.
36
5y-7 = 2y+11 (+7 to both sides) 5y = 2y+18 (- 2y from both sides) 3y = 18 (divide both sides by 3 ) y = 6 y=6