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Can someone explain how to differentiate 1400 v plus 2v 7?
Do you mean 1400v + 2v^7 (is 2v to the power 7)? When you differentiate, e.g. 2v^7, you bring the 7 to the front and reduce the power by 1. If so the answer is 1400 + 7*2v^6 (where * means multiply) or 1400 + 14v^6
How do you factor v to the power of 6 minus 64?
v^6 -64 = (v - 2)(v + 2)(v^2 - 2v + 4)(v^2 + 2v + 4)
What Formula can be used for finding the height of a prism?
Let V be the Volume of the Prism b be the base h be the altitude L be the length of the prism Equation : V=½bhL to find h : 2V=bhL -divide bL to both sides so we get h=2V / bL just simple algebra ..
What are the 5 odd numbers whose sum is 50 from 1 to 19?
It is not possible for five odd numbers to add up to 50 or any even number. All even numbers have the form 2x, where x is an integer, that is if you divide an even number by two you get an integer. All odd numbers have the form 2x + 1, where x is an integer. Another way of looking at this is that every odd number is an even number plus 1. So lets take five odd numbers, 2v+1, 2w+1, 2x+1, 2y+1, and 2z+1, where v, w, x, y, and z are distinct integers. Adding them together we get: (2v+1) + (2w+1) + (2x+1) + (2y+1) + (2z+1) 2v + 2w + 2x + 2y + 2z + 5 2v + 2w + 2x + 2y + 2z + 4 + 1 2(v + w + x + y + z + 1) +1 This is the form of an odd number. Therefore any five odd numbers added together will sum to an odd number.
