3z+2= x ; z=53(5)+215+217Blake watson 63877
3z - 5
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
Since 9z is a multiple of 3z, it is automatically the LCM.
If 3z/2 = 9 then the value of z is 6
Collect all the letters on one side and the numbers on the other; what you do to one side of the equals you do to the other: 3z + 2 = 6z - 13 → 3z +2 - 3z = 6z - 13 - 3z → 2 = 3z - 13 → 2 + 13 = 3z - 13 + 13 → 15 = 3z → 3z = 15 (this is just changing the equals around so that the letter is on the left) → 3z ÷ 3 = 15 ÷ 5 → z = 5
3z+2= x ; z=53(5)+215+217Blake watson 63877
wrong quesion
The answer will be 5
3z - 5
Add like terms to like: (2z - 20) + (3z + 5) = (2z + 3z) + (-20 + 5) = 5z - 15 2z is shorthand for z+z, 3z is shorthand for z+z+z, so: 2z + 3z = (z+z) + (z+z+z) = z+z+z+z+z = 5z Or, to put it another way, just add the coefficients: 2z + 3z = (2+3)z = 5z.
It's rare to see an equation with two equals signs. I'm guessing something else went in between 3z and 9. 3z + 9 = 15, then z = 2 3z - 9 = 15, then z = 8 3z x 9 = 15, then z = 5/9 3z/9 = 15, then z = 45
-47 + 6z = 3z-2-3z -3z-47 + 3z = -2+47 +473z = 45/3 /3z = 15
15 = 3z - 6 15 + 6 = 3z 3z = 21 z = 7
True Observe the following: 5x + 5y + 3z = 5(x + y) + 3z The first two terms could be factored because they shared a common factor of 5, but the third term did not -- not all terms need to share a common factor to use the grouping method.
2(3z - 5)(9z2 + 15z + 25)
Since 9z is a multiple of 3z, it is automatically the LCM.