Possibly, the most common and stable isotope of Nitrogen.
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The quotient of 14 and a number can be represented as 14 ÷ x, where x is the unknown number. This expression simplifies to 14/x. The quotient is not a fixed value unless the specific value of x is known.
n/6 = 14 n = 6*14 n = 84
7 + n = 14 n = 7
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.
Call the smaller of the two consecutive integers n. Then, from the problem statement: n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.