The "Rule subtract 7 in 14 out" refers to a specific mathematical or logical rule that involves taking an input, subtracting 7 from it, and then producing an output that is 14 more than the result of that subtraction. For example, if you start with a number ( x ), the output would be ( (x - 7) + 14 = x + 7 ). This means that the final output is effectively the original input increased by 7.
13
Subtract two.
10/14 - 9/14 = 1/14
Multiply by 3. Then subtract 10.
5/7 - 7/14 becomes: 10/14 - 7/14. Then subtract across to get the final answer: 3/14. 5/7 became 10/14 by finding the lowest common denominator which is 14. Then you figure 7 goes into 14 two times, and 2x5 = 10 therefore 5/7 becomes 10/14.
Double the last digit. Subtract it from the rest. If the result is divisible by 7, the original number is divisible by 7.
13
Subtract two.
Double the last digit and subtract the last digit from the remaining digits.
10/14 - 9/14 = 1/14
(w + 2)(w - 7)
Get a common denominator (14), so you have (10 6/14 ) - (5 7/14). Since 7/14 > 6/14, borrow a 1 from the 10:1 = 14/14, so you have (9 20/14) - (5 7/14). Subtract the fractions and subtract the whole numbers: 413/14
7/8 = 21/24 7/12 = 14/24 21/24 - 14/24 = 7/24
Multiply by 3. Then subtract 10.
That's probably "quotient." 9 x 2 - 14/7 = 18 - 2 = 16
9x + 7 - 2x = 14 Combine like terms: 7x + 7 = 14 Subtract 7 from both sides: 7x = 7 Divide both sides by 7: x = 1
5/7 - 7/14 becomes: 10/14 - 7/14. Then subtract across to get the final answer: 3/14. 5/7 became 10/14 by finding the lowest common denominator which is 14. Then you figure 7 goes into 14 two times, and 2x5 = 10 therefore 5/7 becomes 10/14.