The "Rule subtract 7 in 14 out" refers to a specific mathematical or logical rule that involves taking an input, subtracting 7 from it, and then producing an output that is 14 more than the result of that subtraction. For example, if you start with a number ( x ), the output would be ( (x - 7) + 14 = x + 7 ). This means that the final output is effectively the original input increased by 7.
13
Subtract two.
10/14 - 9/14 = 1/14
Multiply by 3. Then subtract 10.
If the rule is to subtract 3 from a number that starts with 26, you would take the number 26 and subtract 3 from it, resulting in 23. This rule can be applied repeatedly; for instance, if you continue subtracting 3, you would get 20, 17, 14, and so on. The pattern follows a consistent decrease of 3 with each iteration.
Double the last digit. Subtract it from the rest. If the result is divisible by 7, the original number is divisible by 7.
13
Subtract two.
Double the last digit and subtract the last digit from the remaining digits.
10/14 - 9/14 = 1/14
(w + 2)(w - 7)
Get a common denominator (14), so you have (10 6/14 ) - (5 7/14). Since 7/14 > 6/14, borrow a 1 from the 10:1 = 14/14, so you have (9 20/14) - (5 7/14). Subtract the fractions and subtract the whole numbers: 413/14
7/8 = 21/24 7/12 = 14/24 21/24 - 14/24 = 7/24
Multiply by 3. Then subtract 10.
That's probably "quotient." 9 x 2 - 14/7 = 18 - 2 = 16
If the rule is to subtract 3 from a number that starts with 26, you would take the number 26 and subtract 3 from it, resulting in 23. This rule can be applied repeatedly; for instance, if you continue subtracting 3, you would get 20, 17, 14, and so on. The pattern follows a consistent decrease of 3 with each iteration.
9x + 7 - 2x = 14 Combine like terms: 7x + 7 = 14 Subtract 7 from both sides: 7x = 7 Divide both sides by 7: x = 1