If you keep doubling it for one month, you will already have 10737413,11 dollars.
Take the penny a day doubled every day. The sum would be almost 43,000,000.
The equation for the amount you have reached on a given day is 2n-1, where n is the days since starting. For example, on the first day 21-1 = 1 penny, while 2200-1 = 8.035 x 1059 pennies on the two-hundredth day, and 2365-1 = 3.758 x 10109 pennies on the last day. The equation for the whole amount is Σ1365 (2n-1), where the sigma represents the sum of a series and the range is from day 1 to day 365. : Another way of looking at it, which doesn't involve scary "sigma" signs, is this: Whereas X is set equal to "the number of pennies one would receive on the last day of the year after starting with one penny and doubling it every day", then X would equal 2 to the 364th power. 2 to the zeroth power is one. First day. 2 to the first power is two. Second day. 2 to the second power is four. Third day. 2 to the third power is eight. Fourth day. Etc. Note that each power is one less than the day in question. Therefore, 2 to the 364th power would show you how many pennies you would receive on the 365th day. However, one must then perform this equation, for the total number of pennies one would have at the end of the year: 2 to the zeroth plus 2 to the first plus 2 to the second...plus 2 to the 362nd plus 2 to the 363rd plus 2 to the 364th = Y, whereas Y is equal to "the total number of pennies one would have at the end of the year". Yet, an easy short cut is to realize that one need only take the value of X (which is equal to how many pennies you receive on the last day of the year) and subtract one, in order to see how many pennies you had received on the first 364 days of the year total! Then add that amount to X, and you will have Y (which is equal to the total amount of pennies you have for the whole year). Or, X plus (X-1) = Y.
365 pennies = $3.65
Depends on how many working days in a year.
If you keep doubling it for one month, you will already have 10737413,11 dollars.
Take the penny a day doubled every day. The sum would be almost 43,000,000.
The equation for the amount you have reached on a given day is 2n-1, where n is the days since starting. For example, on the first day 21-1 = 1 penny, while 2200-1 = 8.035 x 1059 pennies on the two-hundredth day, and 2365-1 = 3.758 x 10109 pennies on the last day. The equation for the whole amount is Σ1365 (2n-1), where the sigma represents the sum of a series and the range is from day 1 to day 365. : Another way of looking at it, which doesn't involve scary "sigma" signs, is this: Whereas X is set equal to "the number of pennies one would receive on the last day of the year after starting with one penny and doubling it every day", then X would equal 2 to the 364th power. 2 to the zeroth power is one. First day. 2 to the first power is two. Second day. 2 to the second power is four. Third day. 2 to the third power is eight. Fourth day. Etc. Note that each power is one less than the day in question. Therefore, 2 to the 364th power would show you how many pennies you would receive on the 365th day. However, one must then perform this equation, for the total number of pennies one would have at the end of the year: 2 to the zeroth plus 2 to the first plus 2 to the second...plus 2 to the 362nd plus 2 to the 363rd plus 2 to the 364th = Y, whereas Y is equal to "the total number of pennies one would have at the end of the year". Yet, an easy short cut is to realize that one need only take the value of X (which is equal to how many pennies you receive on the last day of the year) and subtract one, in order to see how many pennies you had received on the first 364 days of the year total! Then add that amount to X, and you will have Y (which is equal to the total amount of pennies you have for the whole year). Or, X plus (X-1) = Y.
If you start with one penny on day 1, assuming it's not a leap year, you would end the year with $3.65
Well, doubling your penny could be expressed as 2d where d equals the amount of days you have been doubling. So a year would be 2365 or 7.51533626 X 10109 (109 zeroes). This equates to $751,533,626,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000, 000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000.00 I'm pretty sure that's more than a google. BUT WAIT: THERE'S MORE! If you keep the money from each day, you would need to turn this into a permutation. This means its 2365 X 2264 X 2363X 2362... all the way to 21. This is way too much money and I don't even think there is a name for this number.
If you got a penny on the first day, two more pennies on the second day, four more pennies on the third day, and so on, doubling every day, then: -- On the 17th day, you would get $655.36, pushing your total to $1,310.71 -- The 18th day is the first time you would get more than $1,000 in one day. On that day, you would get $1,310.72, and your total would be $2,621.43 .
365 pennies = $3.65
An equal day and night occurs twice per year on the summer and winter equinox.
The equinoxes are the two dates each year when the day and the night are of equal length.
equinox
equinox
$178.08 a day