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It has infinitely many solutions.

Q: What does it mean if an equation equals 0 does it have one solution no solution or indefinitely many solutions?

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There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)

Since the highest power of 'x' in the equation is '1', there's one solution.

0x2 + 1x - 7 = 0

Related questions

The equation has infinitely many solutions.

One solution: x = -4

16 = 16 is an identity, not an equation. An identity does not have solutions.

There is only one solution to that equation. It's . . . . . x = -16

An equation never equals a number, but its solution often does.-- An equation with a solution of six: [ 3x - 14 = 4 ]-- An equation with a solution of three: [ 14 - 10x = -16 ]-- An equation with both solutions: [ x2 - 9x + 20 = 2 ]An equation that equals 6 is 10 - 4 = 6An equation that equals 3 is 10 - 7 = 3

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There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.

It will have two solutions because its a quadratic equation: x = -8.472135955 or x = 0.472135955

An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.

x - 2y = -6 x - 2y = 2 subtract the 2nd equation from the 1st equation 0 = -8 false Therefore, the system of the equations has no solution.

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There are an infinite number of solutions to this equation, some of which are (9,0), (12,2), (15,4), (18,6), (21,8)