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P2 2pq p2 equals 1

Updated: 4/28/2022
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11y ago

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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.

But my guess is probably not!

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Related questions

What does p2 plus 2pq plus q2 equals 1 represent?

p2+2pq+q2=1


What is q in this equation p2 plus 2pq plus q2 equals 1?

p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p


Who created p2 plus 2pq plus q2 equals 1?

rutherford


Evolution and Genetics I really need the help please The correct equation for the Hardy-Weinberg principle is p2 pq q2 1 p2 2pq q2 1 p 2pq q 1 p pq q 1?

p^2 + 2pq + q^2 = 1


What are the 2 hardy-wienberg equations?

p2 + 2pq + q2 = 1 p+q=1


What does the p2 stand for in the hardy- weinberg equation?

The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype


How do you caluculate the GCD of two prime numbers?

Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2


The Hardy-Weinberg formula and what each of the terms mean?

formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency


What does p2 represent in the Hardy-Weinberg equation?

The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype


The Hardy-Weinberg principle is written as the equation p2 2pq q2 1. What does p represent?

The frequency of the homozygous dominant genotype.


What does p squared represent in p2 plus 2pq plus q2 equals 1?

If restricted to integers, then p is -1, 0 or 1. If restricted to real numbers, then any number in the interval [-1,1]. If not so restricted then any number you like.


What is p2 plus 14p-15 when it equals to zero?

(p=-15)(p=1)