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But my guess is probably not!
When you factor, you take a common polynomial and multiply it by another polynomial (both with the same variable [i.e. both having "y"]) which when solved would create the polynomial in the problem.1) -p2+8p-12-(p-6)(p-2)2) 2y2+15y+7(y+7)(2y+1)3) 6c2+7c+2(2c+1)(3c+2)4) -2b2-5b+12-(b+4)(2b-3)
1 dekaliter equals to 10 liters
Which means 0 = -1!
(1, -1)
One multiplied by one equals one. This is because any number that is multiplied by one equals itself. In this case, it equals one.
p2+2pq+q2=1
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
rutherford
p^2 + 2pq + q^2 = 1
p2 + 2pq + q2 = 1 p+q=1
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
Let p1 and p2 be the two prime numbers. Because they are prime, their divisors are div(p1) = {1,p1} and div(p2) = {1,p2}. So GCD(p1,p2) = Greatest Common Divisor of p1 and p2 = p1 if p1 equals p2 1 if p1 is different from p2
In the Hardy-Weinberg equation, p2 represents the frequency of the homozygous dominant genotype in a population for a specific gene. It represents the proportion of individuals in the population that have two copies of the dominant allele.
If restricted to integers, then p is -1, 0 or 1. If restricted to real numbers, then any number in the interval [-1,1]. If not so restricted then any number you like.
(p=-15)(p=1)
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
p and q represent the frequencies of two types of alleles.