if you have the expression a + b*sqrt(c), the radical conjugate is a - b*sqrt(c).
this is important because multiplying those two expressions together gives you an integer if a, b, and c are integers.
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If you mean, do you distribute a number within a radical to all the terms within the parenthesis than yes it does. Is this what you mean? radical(2)*(a+b) = radical(2)*a + radical(2)*b
An odd number. In the complex field, the number of roots is the same as the index. Complex (non-real) roots come in pairs (complex conjugates) so the number of real roots will also be odd.
If, by "3 radical 27" you mean the cuberoot of 27, the answer is YES. If you mean 3 times sqrt(27), the answer is NO.
if you mean what is square root of 200 in its simplest radical form its 10*21/2
No real roots but the roots are a pair of complex conjugates.