Presuming you meant to write the number with a comma -- 27,456 -- the digit 7 represents 7,000, and holds the "thousandths place":
The digit 2 represents 20,000
The digit 7 represents 7,000
The digit 4 represents 400
The digit 5 represents 50
The digit 6 represents 6
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
3897
27
999 = 27 x 37
27
To find a two-digit number multiplied by a one-digit number that equals 27, we can consider the factors of 27. The two-digit number must be 27 divided by a one-digit factor. The valid combinations are 27 = 9 × 3, where 9 is a one-digit number, and 27 divided by 3 gives us 9, which is also a one-digit number. Therefore, a valid two-digit number multiplied by a one-digit number to get 27 does not exist since 27 itself is a two-digit number.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
27
3897
3897
27
27, 57, 77 and 87.
999 = 27 x 37
The product of 3 times 9 is 27. In the number 27, the tens digit is 2.
999
Assuming that didgets(?) is meant to be digits, a 27 digit number would be hundreds of septillions.
The difference between 8 times the last digit and the rest of the number is a multiple of 27