Y-8x plus 9y equals 10y-8x.
y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.
the slope is 6 and the y intercept is 8x
Y=8x-3
11
10
10
If: y = kx+1 is a tangent to the curve y^2 = 8x Then k must equal 2 for the discriminant to equal zero when the given equations are merged together to equal zero.
Y-8x plus 9y equals 10y-8x.
y = x2 + 8x + 15 = (x + 3)(x + 5). When y = 0, one or other of the two factors must equal zero; that is, x = -3 or -5, when y = 0.
the slope is 6 and the y intercept is 8x
-8x-8y=-64 -8y=8x-64 y=-x+8
Complementary angles add up to 90 degrees so if y = 8x-20 degrees then the complement of y is 90 - (8x - 20) = 110 - 8x degrees.
If y = kx+1 is a tangent to the curve of y^2 = 8x Then it works out that k has a value of 2 and that x has equal roots of 1/2 -------------------------------------- y = kx + 1 and y² = 8x meet when they are equal, ie (substituting for y): (kx + 1)² = 8x → k²x² + 2kx + 1 = 8x → k²x² +(2k - 8)x + 1 = 0 If y = kx + 1 is tangent to y² = 8x, they meet at one point; this occurs when the above quadratic has a repeated root; which happens when the discriminant b² - 4ac = 0, namely: (2k - 8)² - 4 × k² × 1 = 0 → 4k² - 32k + 64 - 4k² = 0 → 32k = 64 → k = ½
8x-36 equal = -28
If you mean: -8x+y = 2 then y = 8x+2 and the line parallel to it will have the same slope of 8 but with a different y intercept.
No.