Log4 64=y 64=4y 26=22y Therefore y=3
If x=6 and y=8, then [ 5x + 8y ] = 5(6) + 8(8) = 30 + 64 = 94
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
It is: (81*9*64)+19 = 46,675
x = 2 so x squared = 4 and 2x squared = 2 times 4 = 8; y = 4 so xy = 2 times 4 = 8 and 3xy = 3 times 8 = 24; y squared = 4 times 4 = 16 and 4y squared = 4 times 16 = 64; so 8 + 24 - 64 = 32 - 64 = -32
Log4 64=y 64=4y 26=22y Therefore y=3
8x8 = 64 so it is 64 (the y) 3x4 = 12 so it is 12 (the x) 64+12 is 76.
If y=8, then 8 squared is 64.
y=8
y2 - 16y + 64 = 0 (y - 8)2 = 0 y - 8 = 0 y = 8
x = 2, y = 84x + 8y= 4(2) + 8(8)= 8 + 64= 72
If x=6 and y=8, then [ 5x + 8y ] = 5(6) + 8(8) = 30 + 64 = 94
To determine slope and Y intercept, solve the equation for y... 5x - 8y + 64 = 0 -8y = -5x - 64 8y = 5x + 64 y = 5/8x + 8 ... now that you have the equation in the form y = mx + b, you can easily see that the slope is 5/8, and the Y intercept is 8.
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
find x3+y2 if x=4 and y=3 ( 4*4*4)+(3*3) 64 +9 =73
Y =sqrt(4x^2 +64/16) I would, after factoring, say +/- 2; horizontally
64-3 equals = 61