Potassium.
L-1 electron configuration
Scandium is a transition element, so it has properties quite different. so instead of having 2-8-8-3 it sends 1 electron to the inner L shell and becomes 2-8-9-2
D. S-2Electron configuration has to do with the number of electrons, so using a Periodic table, it is easy to find this answer.For example, O-2 has 2 more electrons than usual, so move two spaces to the right, which is neon.For F- , it is the same way. Since it is a minus 1, move one space to the right, which is neon.For Al+3 there are 3 LESS electrons than usual so move back(to the right) 3 spaces, which is neon.For S-2 , the answer to your problem, has the same electron configuration as Argon.For Mg+2 there are 2 less electrons so moving back 2 spaces gives you neon.Remember 'minus' means more electrons so for electron configurations you move forward on the Periodic table for ions with negative charge and backwards if the ion is positive.
A 4d electron; that is for apex :)
A set "A" is said to be a subset of "B" if all elements of set "A" are also elements of set "B".Set "A" is said to be a proper subset of set "B" if: * A is a subset of B, and * A is not identical to B In other words, set "B" would have at least one element that is not an element of set "A". Examples: {1, 2} is a subset of {1, 2}. It is not a proper subset. {1, 3} is a subset of {1, 2, 3}. It is also a proper subset.
There is no element such as 12M. Assuming that you mean 12Mg, the electron configuration is 2, 8, 2.
Sodium.
The atomic number of zinc is 30. Its abbreviated electron configuration is [Ar]4s23d10 The full electron configuration is 1s22s22p63s23p64s23d10 (configurations for the atom in its ground state. Ions and excited atoms have different configurations).
2-2
Zinc has this electron configuration.
All elements in group 1 have 1 valence electron.
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It loses 2 electrons and becomes a +2 ion.
[Ne] 3s2 3p5 or 2, 8, 7
Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^1 Short-hand version: [Ne] 3s^2 3p^1 Note: The "^" symbol means the the following number is in the form of a superscript.
the condensed electron configuration for Lu is [Xe] 6s^2 4f^14 5d^1
With it being a dipositive ion, the original element has lost 2 electrons. Making the configuration 1s2 2s2 2p6 3s2 2p4. That Configuration is Sulfur.