Scandium is a transition element, so it has properties quite different. so instead of having 2-8-8-3 it sends 1 electron to the inner L shell and becomes 2-8-9-2
Potassium.
L-1 electron configuration
D. S-2Electron configuration has to do with the number of electrons, so using a Periodic table, it is easy to find this answer.For example, O-2 has 2 more electrons than usual, so move two spaces to the right, which is neon.For F- , it is the same way. Since it is a minus 1, move one space to the right, which is neon.For Al+3 there are 3 LESS electrons than usual so move back(to the right) 3 spaces, which is neon.For S-2 , the answer to your problem, has the same electron configuration as Argon.For Mg+2 there are 2 less electrons so moving back 2 spaces gives you neon.Remember 'minus' means more electrons so for electron configurations you move forward on the Periodic table for ions with negative charge and backwards if the ion is positive.
2*2 is 4. like 2+2=4
It is like this if you are doing 2 squared you do 2 *2 = 4
Electronic configuration of scandium: [Ar]3d1.4s2 Electrons per shell: 2, 8, 9, 2
Scandium has four electronic shells with 2, 8, 9, 2 electrons.
The electronic configuration of Calcium is 2-8-8-2, therefore the valency of Calcium is +2.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
The electronic configuration of Fe3+ is [Ar] 3d3 4s2 or 2, 8, 11, 2
The electronic configuration of calcium in calcium hydroxide is the configuration of a calcium +2 ion, which is the same as the configuration of the preceding noble gas, argon.
2
2-8-8-2
The electronic configuration for iodine is [Kr] 4d^10 5s^2 5p^5 2, 8, 18, 18, 7.
Oxygen receives 2 electrons, so it has the electronic configuration like neon.
Scandium is in the group 3, calcium in the group 2 of the periodic table.
The electronic configuration of sulfur ion (S)2- is: 1s22s22p63s23p6.