It is divisible by any of its factors
It is divisible by any of its factors
To determine which numbers 4518 is divisible by, we need to check divisibility rules for common factors. 4518 is divisible by 2 because the last digit is even. It is also divisible by 3 because the sum of its digits (4+5+1+8=18) is divisible by 3. Additionally, 4518 is divisible by 6 since it is divisible by both 2 and 3.
The factors of 234 are 1, 2, 3, 6, 9, 13, 18, 26, 39, 78, 117, and 234
It is divisible by 1 and 2, amongst other factors.
The factors of 18 are: 1, 2, 3, 6, 9, 18 The factors of 49 are: 1, 7, 49
The factors of 18 are: 1, 2, 3, 6, 9, 18The factors of 28 are: 1, 2, 4, 7, 14, 28
The sum of the factors are divisible by 9. Ex: 738 7+3+8=18 18/9=2
No, 8 is not a factor of 18, but 1, 2, 3, 6, and 9 are factors of 18.
The only common factors I can see are 1 and 2. 18 is divisible by 1,2,3,6, and 9, and 26 is divisible by 1,2,13,and 26.
18, 24, 32, 36
20 is not divisible by 18.
18 is not divisible by 5 and 7.
138 is not divisible by 18.
Well, honey, any number that is divisible by 6 is automatically divisible by 2. So, the numbers that are divisible by both 6 and 2 are simply the multiples of 6. In other words, any number that can be written as 6 multiplied by another whole number. Math can be a piece of cake when you break it down like that!
-- Neither 2 nor 5 is divisible by 18. -- 18 is divisible by 2, but not by 5.
Yes, a number that is divisible by both 2 and 6 will always be divisible by 12. This is because 12 is the least common multiple of 2 and 6. Any number that is divisible by both 2 and 6 will also have all the factors of 12, making it divisible by 12 as well.