4/7
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There are 21 consonants in the English alphabet (B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Y, Z). There are a total of 26 letters in the English alphabet. To find the fraction of the alphabet that is made up of consonants, you would divide the number of consonants by the total number of letters, which gives you 21/26. Therefore, approximately 80.77% of the English alphabet is made up of consonants.
3 out of 7 or 3/7.
In the word DAUGHTER, there are 3 vowels namely, A, U, and E, and 5 consonants namely, D, G, H, T, and R. Number of ways of selecting 2 vowels out of 3 vowels = Number of ways of selecting 3 consonants out of 5 consonants = Therefore, number of combinations of 2 vowels and 3 consonants = 3 × 10 = 30 Each of these 30 combinations of 2 vowels and 3 consonants can be arranged among themselves in 5! ways. Hence, required number of different words = 30 × 5! = 3600
3/8 (specifically u, t and p out of the eight different letters in "multiply").
You have written 6 of them in your question - what, words, consonants, next, each, other I hope this helps